The ratio of the incomes of two employees is $7 : 4$, and the ratio of their expenditures is $3 : 1$. Each of them manages to save ₹4,800 per month. Find the sum of their monthly incomes (in ₹).

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**Solution:**

1. Let the incomes of the two employees be $7x$ and $4x$ respectively.
2. Let their expenditures be $3y$ and $y$ respectively.
3. Given that each saves ₹4,800 per month, so:
   - Savings of first employee = Income - Expenditure = $7x - 3y = 4800$  ...(1)
   - Savings of second employee = $4x - y = 4800$  ...(2)

4. From equation (2), express $y$ in terms of $x$:
   $$y = 4x - 4800$$

5. Substitute $y$ into equation (1):
   $$7x - 3(4x - 4800) = 4800$$
   $$7x - 12x + 14400 = 4800$$
   $$-5x + 14400 = 4800$$
   $$-5x = 4800 - 14400 = -9600$$
   $$x = \frac{9600}{5} = 1920$$

6. Calculate $y$:
   $$y = 4(1920) - 4800 = 7680 - 4800 = 2880$$

7. Sum of their incomes:
   $$7x + 4x = 11x = 11 	imes 1920 = 21120$$

**Answer:** ₹21,120

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