40 litres of milk are kept in a container. 4 litres of milk were removed from this container and replaced with water. This procedure was performed two more times. How much milk does the container now hold?

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**Solution:**

1. Initial quantity of pure milk, *A* = 40 litres
2. Quantity replaced each time, *B* = 4 litres
3. Number of times the operation is performed, *n* = 3

Using the formula for repeated replacement:

$$	ext{Quantity of pure milk after } n 	ext{ operations} = A 	imes \left(1 - \frac{B}{A}ight)^n$$

Substitute the values:

$$= 40 	imes \left(1 - \frac{4}{40}ight)^3 = 40 	imes \left(1 - 0.1ight)^3 = 40 	imes (0.9)^3$$

Calculate:

$$= 40 	imes 0.729 = 29.16 	ext{ litres}$$

**Answer:** 29.16 litres

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