A light bulb working on a 18 V battery draws a current of 3 A. What will be the resistance of the bulb?

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**Solution:**

1. According to Ohm's law, resistance $ R $ is given by:
   $$ R = \frac{V}{I} $$

2. Given voltage $ V = 18 \text{ V} $ and current $ I = 3 \text{ A} $, substitute the values:
   $$ R = \frac{18}{3} = 6 \ \Omega $$

3. Therefore, the resistance of the bulb is $ 6 \ \Omega $.

**Answer:** 6 $ \Omega $

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