Six teachers are to stand in a row, where two are primary teachers, two are middle teachers, and two are secondary teachers. The arrangement must ensure that the primary, middle, and secondary teachers always form distinct groups. In how many ways can this arrangement be done?

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**Step 1: Arrange teachers within each group.**  
- **Primary teachers (2):** They can be arranged within their group in $$2! = 2$$ ways.  
- **Middle teachers (2):** They can be arranged within their group in $$2! = 2$$ ways.  
- **Secondary teachers (2):** They can be arranged within their group in $$2! = 2$$ ways.

**Step 2: Arrange the three groups themselves.**  
The three groups (primary, middle, secondary) can be arranged in $$3! = 6$$ ways.

**Step 3: Calculate the total number of arrangements.**  
Multiply the internal arrangements of each group by the arrangements of the groups:  
$$
	ext{Total arrangements} = 2 	imes 2 	imes 2 	imes 6 = 48
$$

Thus, the required number of ways to arrange the teachers is **48**.

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