Three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which is the letter-cluster pair that does NOT belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their positions in the letter-cluster.)

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Accepted Answer

Let's analyze each pair:

1. EJ - OT
   - E (5th letter), J (10th letter)
   - O (15th letter), T (20th letter)
   - Difference between E and J: 10 - 5 = 5
   - Difference between O and T: 20 - 15 = 5

2. PF - OI
   - P (16th letter), F (6th letter)
   - O (15th letter), I (9th letter)
   - Difference between P and F: 16 - 6 = 10
   - Difference between O and I: 15 - 9 = 6

3. KP - UZ
   - K (11th letter), P (16th letter)
   - U (21st letter), Z (26th letter)
   - Difference between K and P: 16 - 11 = 5
   - Difference between U and Z: 26 - 21 = 5

4. CH - MR
   - C (3rd letter), H (8th letter)
   - M (13th letter), R (18th letter)
   - Difference between C and H: 8 - 3 = 5
   - Difference between M and R: 18 - 13 = 5

Observation:
- In options 1, 3, and 4, both pairs have a difference of 5 between the two letters in each cluster.
- In option 2 (PF - OI), the differences are 10 and 6, which do not match and are not 5.

Therefore, the pair that does NOT belong to the group is PF - OI.

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