Simplify
$$
\frac{(8.3)^3 + (9.2)^3 + (6.1)^3 - 3 imes 8.3 imes 9.2 imes 6.1}{(8.3)^2 + (9.2)^2 + (6.1)^2 - 8.3 imes 9.2 - 9.2 imes 6.1 - 6.1 imes 8.3}
$$

Question

Simplify  
$$
\frac{(8.3)^3 + (9.2)^3 + (6.1)^3 - 3 	imes 8.3 	imes 9.2 	imes 6.1}{(8.3)^2 + (9.2)^2 + (6.1)^2 - 8.3 	imes 9.2 - 9.2 	imes 6.1 - 6.1 	imes 8.3}
$$

Accepted Answer

The numerator:
$$
a^3 + b^3 + c^3 - 3abc
$$
The denominator:
$$
a^2 + b^2 + c^2 - ab - bc - ca
$$

Recall the identity:
$$
a^3 + b^3 + c^3 - 3abc = (a + b + c)\left(a^2 + b^2 + c^2 - ab - bc - ca\right)
$$

So,
$$
\frac{a^3 + b^3 + c^3 - 3abc}{a^2 + b^2 + c^2 - ab - bc - ca} = a + b + c
$$

Now, substitute the values:
$$
a + b + c = 8.3 + 9.2 + 6.1 = 23.6
$$

**Thus, the answer is 23.6.**

Answer

Answer

Answer