At present, A is thrice as old as B. C is 5 years elder than B. The sum of the ages of A, B, and C is 75 years. What is the ratio of the age of B five years ago to the age of A three years from now?

Question

Accepted Answer

Let the present age of B be x years.
Then, present age of A = 3x years.
C is 5 years elder than B, so present age of C = x + 5 years.

Sum of ages: A + B + C = 75
=> 3x + x + (x + 5) = 75
=> 5x + 5 = 75
=> 5x = 70
=> x = 14

So, B's present age = 14 years
A's present age = 3x = 42 years
C's present age = x + 5 = 19 years

B's age five years ago = 14 - 5 = 9 years
A's age three years from now = 42 + 3 = 45 years

Required ratio = 9 : 45 = 1 : 5

Wait, let's check the options and calculation carefully:

B's age five years ago = 14 - 5 = 9
A's age three years from now = 42 + 3 = 45
Ratio = 9 : 45 = 1 : 5

Let's check the calculation step by step:

Let B = x
A = 3x
C = x + 5
Sum: 3x + x + x + 5 = 75
=> 5x + 5 = 75
=> 5x = 70
=> x = 14

So B = 14, A = 42, C = 19

B five years ago = 9
A three years from now = 45
Ratio = 9 : 45 = 1 : 5

So the correct answer should be 1:5. The correct option is option 4.

Final Answer: Option 4 (1:5)

Answer

Answer

Answer