Which of the following is the largest 5-digit number divisible by 47?

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Accepted Answer

To find the largest 5-digit number divisible by 47, start with the largest 5-digit number, which is 99999. Divide 99999 by 47:

99999 ÷ 47 = 2127.638...

The integer part is 2127. Multiply 47 × 2127 = 99969.

So, 99969 is the largest 5-digit number divisible by 47.

Checking the options:
- 99999 is not divisible by 47.
- 98888 ÷ 47 = 2104.00 (2104 × 47 = 98888), so 98888 is divisible by 47, but it's less than 99969.
- 99969 is divisible by 47 (as shown above).
- 10000 ÷ 47 ≈ 212.77 (not an integer).

Therefore, the correct answer is 99969.

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