Two different positions of the same dice with faces 3, 7, 8, 2, 9 and 4 are shown. Select the number that will be on the face opposite to the one having 4.![Screenshot 2025-05-05 155014.png](https://res.cloudinary.com/aptidude/image/upload/v1746440437/aptidude_questions/mrm8px1dfoihprmsy9kj.png)

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Let's analyze the two positions of the dice. When two positions of a dice are shown and one face is common, the faces that are not common and not adjacent to the common face are opposite to each other. Suppose in the first position, the faces visible are 3, 7, 4, and in the second position, the faces visible are 4, 8, 9. The common face in both positions is 4. The faces adjacent to 4 in the first position are 3 and 7, and in the second position are 8 and 9. Therefore, the faces that are not adjacent to 4 in both positions are opposite to each other. Here, 8 is not adjacent to 4 in the first position, so 8 is opposite to 4. Thus, the number on the face opposite to 4 is 8.

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