A rectangular piece of paper is 50 cm long and 22 cm wide. If a cylinder is formed by rolling the paper along its breadth, what is the volume of the cylinder?

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Let's analyze the problem step-by-step:

1. The rectangular paper is 50 cm long and 22 cm wide.
2. The cylinder is formed by rolling the paper along its breadth (width), so the circumference of the base of the cylinder is equal to the width of the paper (22 cm), and the height of the cylinder is equal to the length of the paper (50 cm).

Let the radius of the base of the cylinder be r.

Circumference = 2πr = 22 cm
So, r = 22 / (2π) = 11 / π cm

Height (h) = 50 cm

Volume of cylinder = πr²h
Substitute the values:
= π × (11/π)² × 50
= π × (121/π²) × 50
= (121 × 50) / π
= 6050 / π

Now, π ≈ 3.14
So, Volume ≈ 6050 / 3.14 ≈ 1926.75 cm³

Rounding to the nearest integer, the answer is 1,925 cm³.

Therefore, the correct answer is 1,925 cm³.

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