A sum of money is divided among P, Q, R and S in the proportion of 4 : 9 : 2 : 3. If Q gets ₹560 more than R, then what is the share of S?

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Accepted Answer

Let the common multiplier for the shares be x.

Given the ratio of shares: P : Q : R : S = 4 : 9 : 2 : 3

So, Q's share = 9x, R's share = 2x.

Given Q gets ₹560 more than R:
9x - 2x = 560
7x = 560
x = 560 / 7 = 80

Now, S's share = 3x = 3 * 80 = ₹240.

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