Find the area of a square, one of whose diagonals is 4.8 m long.

Question

Accepted Answer

Let the side of the square be 'a'. The diagonal of a square is given by the formula: diagonal = a√2.

Given diagonal = 4.8 m,

So, a√2 = 4.8
=> a = 4.8 / √2
=> a = 4.8 / 1.4142 ≈ 3.394 m

Area of square = a² = (3.394)² ≈ 11.52 m².

Hence, the area of the square is 11.52 m².

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