Find the smallest value that must be assigned to number ‘a’ in order for 91876a2 to be divisible by 8.

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To check divisibility by 8, the last three digits of the number must be divisible by 8.

The last three digits here are '6a2'. We need to find the smallest digit 'a' such that the number 6a2 is divisible by 8.

Let's check for each value of 'a' from 0 to 9:
- 602 ÷ 8 = 75.25 (not divisible)
- 612 ÷ 8 = 76.5 (not divisible)
- 622 ÷ 8 = 77.75 (not divisible)
- 632 ÷ 8 = 79 (divisible)

Since 632 is divisible by 8, the smallest value of 'a' is 3.

Therefore, the answer is 3.

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