Two pipes A and B can fill a tank in 1 1/3 hours and 2 hours, respectively. If both the pipes are opened simultaneously, then in how much time will the tank be filled?

Question

Accepted Answer

Step 1: Convert the times into improper fractions or decimals for easier calculation.
- Pipe A fills the tank in 1 1/3 hours = 4/3 hours.
- Pipe B fills the tank in 2 hours.

Step 2: Calculate the rate of filling for each pipe.
- Rate of A = 1 tank / (4/3) hours = 3/4 tank per hour.
- Rate of B = 1 tank / 2 hours = 1/2 tank per hour.

Step 3: Calculate the combined rate when both pipes are opened simultaneously.
- Combined rate = 3/4 + 1/2 = 3/4 + 2/4 = 5/4 tank per hour.

Step 4: Calculate the time taken to fill the tank together.
- Time = 1 tank / (5/4) tank per hour = 4/5 hours.

Step 5: Convert 4/5 hours into minutes.
- 4/5 hours = 0.8 hours = 0.8 × 60 = 48 minutes.

Rechecking calculations:

Recalculation:
- A fills in 1 1/3 hours = 4/3 hours.
- Rate A = 3/4 tank/hour.
- Rate B = 1/2 tank/hour.
- Combined rate = 3/4 + 1/2 = 5/4 tank/hour.
- Time = 1 / (5/4) = 4/5 hours = 0.8 hours = 48 minutes.

Therefore, the correct answer is 48 minutes (option 3).

Answer

Answer

Answer