Which letter-cluster will replace the question mark (?) to complete the given series: BKUZ, ENWB, ?, KTAF, NWCH?

Question

Accepted Answer

Let's analyze the given series: BKUZ, ENWB, ?, KTAF, NWCH.

Step 1: Write down the positions of letters in the alphabet (A=1, B=2, ..., Z=26):
B(2) K(11) U(21) Z(26)
E(5) N(14) W(23) B(2)
? ? ? ?
K(11) T(20) A(1) F(6)
N(14) W(23) C(3) H(8)

Step 2: Find the pattern for each letter position across the series.

First letters: 2 (B), 5 (E), ?, 11 (K), 14 (N)
Differences: 5-2=3, ?-5=?, 11-?=?, 14-11=3
The pattern seems to be +3 each time.
So, 2 + 3 = 5 (E), 5 + 3 = 8 (H), 8 + 3 = 11 (K), 11 + 3 = 14 (N)
So the missing first letter is H (8).

Second letters: 11 (K), 14 (N), ?, 20 (T), 23 (W)
Differences: 14-11=3, ?-14=?, 20-?=?, 23-20=3
Again, +3 each time.
So, 14 + 3 = 17 (Q), 17 + 3 = 20 (T), 20 + 3 = 23 (W)
So the missing second letter is Q (17).

Third letters: 21 (U), 23 (W), ?, 1 (A), 3 (C)
Note that after W(23), the next letter is ?, then A(1), C(3).
Let's consider the alphabet as circular (after Z(26) comes A(1)).
From U(21) to W(23): +2
From W(23) to ?: ?
From ? to A(1): ?
From A(1) to C(3): +2
If we assume the pattern is +2 each time, then:
21 + 2 = 23 (W)
23 + 2 = 25 (Y)
25 + 2 = 27 → 27 - 26 = 1 (A)
So the missing third letter is Y (25).

Fourth letters: 26 (Z), 2 (B), ?, 6 (F), 8 (H)
From Z(26) to B(2): 26 to 2 is +2 (considering circular: 26 + 2 = 28 → 28 - 26 = 2)
From B(2) to ?: ?
From ? to F(6): ?
From F(6) to H(8): +2
So pattern is +2 each time.
2 + 2 = 4 (D)
4 + 2 = 6 (F)
6 + 2 = 8 (H)
So the missing fourth letter is D (4).

Step 3: Combine the missing letters: H (8), Q (17), Y (25), D (4) → HQYD

Step 4: Check options:
Option 2 is HQYD, which matches our result.

Therefore, the correct answer is HQYD.

Answer

Answer

Answer