Three of the following four letter-clusters are alike in a certain way and thus form a group. Which is the letter-cluster that does NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their positions in the letter-cluster.)

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Accepted Answer

Let's analyze the letter-clusters: MPR, CFH, IKN, EHJ.

Step 1: Check the alphabetical positions of letters:
- M (13), P (16), R (18)
- C (3), F (6), H (8)
- I (9), K (11), N (14)
- E (5), H (8), J (10)

Step 2: Check the differences between consecutive letters:
- MPR: P - M = 3, R - P = 2
- CFH: F - C = 3, H - F = 2
- IKN: K - I = 2, N - K = 3
- EHJ: H - E = 3, J - H = 2

Step 3: Observe the pattern:
- MPR, CFH, and EHJ have differences of 3 and then 2 between consecutive letters.
- IKN has differences of 2 and then 3.

Thus, IKN is the odd one out because the pattern of differences between letters is reversed compared to the other three clusters.

However, the question states the odd one out is NOT based on the number of consonants/vowels or their positions, but the difference pattern is a valid distinguishing factor.

Therefore, the letter-cluster that does NOT belong to the group is IKN.

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