The number of appeared candidates from State Z increased by 100% from 2008 to 2009. If the total number of qualified candidates from State Z in 2008 and 2009 together is 552, what is the number of appeared candidates from State Z in 2009?

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1748021579/aptidude_questions/jb0h136cuywvpdqtyjdu.png)

Question

The number of appeared candidates from State Z increased by 100% from 2008 to 2009. If the total number of qualified candidates from State Z in 2008 and 2009 together is 552, what is the number of appeared candidates from State Z in 2009?

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1748021579/aptidude_questions/jb0h136cuywvpdqtyjdu.png)

Accepted Answer

Step 1: Let the number of appeared candidates from State Z in 2008 be x.

Step 2: According to the problem, the number of appeared candidates from State Z increased by 100% from 2008 to 2009. This means the number doubled in 2009.

So, appeared candidates in 2009 = 2x.

Step 3: Percentage of qualified candidates from State Z in 2008 is 70%, so qualified candidates in 2008 = 70% of x = 0.7x.

Step 4: Percentage of qualified candidates from State Z in 2009 is 80%, so qualified candidates in 2009 = 80% of 2x = 1.6x.

Step 5: Total qualified candidates from State Z in 2008 and 2009 together = 552.

So, 0.7x + 1.6x = 552

=> 2.3x = 552

=> x = 552 / 2.3 = 240

Step 6: Number of appeared candidates from State Z in 2009 = 2x = 2 * 240 = 480.

Therefore, the number of appeared candidates from State Z in 2009 is 480.

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