A thief is spotted by a policeman from a distance of 195 metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 22 km/h and that of the policeman is 27 km/h, then how far would the thief have run (in meters) before he is overtaken?

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Step 1: Convert speeds from km/h to m/s.
- Speed of thief = 22 km/h = (22 * 1000) / 3600 = 22000 / 3600 ≈ 6.11 m/s
- Speed of policeman = 27 km/h = (27 * 1000) / 3600 = 27000 / 3600 = 7.5 m/s

Step 2: Calculate relative speed of policeman with respect to thief:
Relative speed = 7.5 - 6.11 = 1.39 m/s

Step 3: Distance between policeman and thief initially = 195 m

Step 4: Time taken for policeman to catch thief = Distance / Relative speed = 195 / 1.39 ≈ 140.29 seconds

Step 5: Distance run by thief in this time = speed of thief * time = 6.11 * 140.29 ≈ 856.4 m

Rounding to nearest integer, the thief runs approximately 858 meters before being overtaken.

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