One pipe can fill a tank 6 times faster than another pipe. If both the pipes together can fill the tank in 40 minutes, then in how many minutes will the slower pipe alone be able to fill the tank?

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Let the slower pipe fill the tank in x minutes. Then the faster pipe fills the tank 6 times faster, so it fills the tank in x/6 minutes.

The rate of the slower pipe = 1/x (tank per minute)
The rate of the faster pipe = 6/x (tank per minute)

Together, their combined rate = 1/40 (tank per minute)

So, (1/x) + (6/x) = 1/40
=> 7/x = 1/40
=> x = 7 * 40 = 280 minutes

Therefore, the slower pipe alone will fill the tank in 280 minutes.

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