In a certain code language, ‘IFF’ is coded as ‘21’ and ‘ARB’ is coded as ‘21’. How will ‘CAW’ be coded in that language?

Question

Accepted Answer

Step 1: Assign numerical values to letters based on their position in the alphabet (A=1, B=2, ..., Z=26).

For 'IFF':
I = 9
F = 6
F = 6
Sum = 9 + 6 + 6 = 21

For 'ARB':
A = 1
R = 18
B = 2
Sum = 1 + 18 + 2 = 21

Both words are coded as 21, which is the sum of the positions of their letters.

Step 2: Calculate the code for 'CAW':
C = 3
A = 1
W = 23
Sum = 3 + 1 + 23 = 27

Step 3: Check options. 27 is option 3, but the answer given is 25. Let's re-examine.

Possibility: Maybe the code is sum of letters minus number of letters.

For 'IFF': sum = 21, letters = 3, 21 - 3 = 18 (doesn't match 21)
For 'ARB': sum = 21, letters = 3, 21 - 3 = 18 (doesn't match 21)

Possibility: Sum of letters minus position of first letter?

For 'IFF': 21 - 9 = 12 (no)
For 'ARB': 21 - 1 = 20 (no)

Possibility: Sum of letters minus position of last letter?

For 'IFF': 21 - 6 = 15 (no)
For 'ARB': 21 - 2 = 19 (no)

Possibility: Sum of letters minus position of middle letter?

For 'IFF': 21 - 6 = 15 (no)
For 'ARB': 21 - 18 = 3 (no)

Possibility: Sum of letters minus 1 for each repeated letter?

In 'IFF', F repeats twice, so subtract 1 for each repetition (1 repetition): 21 - 1 = 20 (no)

No clear pattern other than sum of letters.

Given both 'IFF' and 'ARB' sum to 21 and are coded as 21, the code is sum of letter positions.

Therefore, 'CAW' sum is 3 + 1 + 23 = 27.

Hence, the correct code for 'CAW' is 27 (option 3).

Final answer: 27.

Answer

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