![image.png](https://res.cloudinary.com/aptidude/image/upload/v1748080155/aptidude_questions/zs8jfyv3qolc6werqeuu.png)

What was the percentage of students who passed in the first division in 2009?

Question

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1748080155/aptidude_questions/zs8jfyv3qolc6werqeuu.png)

What was the percentage of students who passed in the first division in 2009?

Accepted Answer

Step 1: Identify the number of students in the first division in 2009 from the table: 30 students.
Step 2: Calculate the total number of students who passed in 2009. Passing students are those in 1st, 2nd, and 3rd divisions.
Number of students passed = 1st division + 2nd division + 3rd division = 30 + 60 + 50 = 140.
Step 3: Calculate the percentage of students who passed in the first division:
(First division students / Total passed students) × 100 = (30 / 140) × 100 = (3/14) × 100 = 21.4285%.
Step 4: The options are in mixed fraction form. Let's convert 15 (15/19) % to decimal:
15 + 15/19 = 15 + 0.7895 = 15.7895% which is not matching 21.43%.
Step 5: Re-examine the question: It asks for percentage of students who passed in first division in 2009.
Step 6: Possibly the question means percentage of first division students out of total students (including fail).
Total students in 2009 = 30 + 60 + 50 + 50 = 190.
Percentage = (30 / 190) × 100 = 15.7895% = 15 (15/19) %.
Step 7: Hence, the correct interpretation is percentage of first division students out of total students in 2009, which matches option 4.
Therefore, the correct answer is 15 (15/19) %.

Answer

Answer

Answer