△ABC is a right-angled triangle with ∠ABC = 90°. If the length of AB is 28 cm and the length of BC is 96 cm, find the area (in cm²) of the circumcircle of △ABC. Use π = 3.14.

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Given △ABC is right-angled at B, with AB = 28 cm and BC = 96 cm.

Step 1: Find the length of the hypotenuse AC using Pythagoras theorem:
AC = √(AB² + BC²) = √(28² + 96²) = √(784 + 9216) = √10000 = 100 cm.

Step 2: The circumcircle of a right-angled triangle has its diameter as the hypotenuse.
So, diameter of circumcircle = AC = 100 cm.

Step 3: Radius of circumcircle = diameter / 2 = 100 / 2 = 50 cm.

Step 4: Area of the circumcircle = π * r² = 3.14 * 50² = 3.14 * 2500 = 7850 cm².

Therefore, the area of the circumcircle is 7,850 cm².

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