The salaries of three friends Sita, Gita, and Mita are initially in the ratio **5 : 6 : 7**, respectively. In the first year, they get salary hikes of **20%**, **25%**, and **20%**, respectively. In the second year, Sita and Mita get salary hikes of **40%** and **25%**, respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is:

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Let the initial salaries of Sita, Gita, and Mita be $$ 5x $$, $$ 6x $$, and $$ 7x $$, respectively.

#### Step 1: Salaries after first-year hikes
- Sita's salary: $$ 5x 	imes 1.2 = 6x $$.  
- Gita's salary: $$ 6x 	imes 1.25 = 7.5x $$.  
- Mita's salary: $$ 7x 	imes 1.2 = 8.4x $$.

#### Step 2: Salaries after second-year hikes
- Sita gets a hike of **40%**:  
$$ 6x 	imes 1.4 = 8.4x $$.  
- Mita gets a hike of **25%**:  
$$ 8.4x 	imes 1.25 = 10.5x $$.  
- Gita's salary becomes equal to the mean of the three salaries in the second year.

#### Step 3: Calculate Gita's second-year salary
The mean salary is given by:  
$$ 	ext{Mean} = \frac{	ext{Sita's Salary} + 	ext{Gita's Salary} + 	ext{Mita's Salary}}{3}. $$  
Let Gita's second-year salary be $$ y $$. Then:  
$$ y = \frac{8.4x + y + 10.5x}{3}. $$

Simplify:  
$$ y = \frac{18.9x + y}{3}. $$  
Multiply through by 3:  
$$ 3y = 18.9x + y. $$  
Rearrange terms:  
$$ 2y = 18.9x. $$  
Solve for $$ y $$:  
$$ y = \frac{18.9x}{2} = 9.45x. $$

#### Step 4: Calculate Gita’s hike percentage
Gita’s hike percentage in the second year is:  
$$ 	ext{Hike} = \frac{	ext{New Salary} - 	ext{Old Salary}}{	ext{Old Salary}} 	imes 100. $$  
Substitute values:  
$$ 	ext{Hike} = \frac{9.45x - 7.5x}{7.5x} 	imes 100 = \frac{1.95}{7.5} 	imes 100 = 26\%. $$

Thus, Gita’s salary hike in the second year is **26%**.

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