Six numbers 5, 3, 6, 7, 9 and 2 are written on different faces of a dice. Two positions of this dice are shown in the figure below. Find the number on the face opposite to the one having 5.
![image.png](https://res.cloudinary.com/aptidude/image/upload/v1748344188/aptidude_questions/rlvcxuzfew0af9d0twmc.png)

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A standard dice has six faces with numbers on each face. The numbers on opposite faces always add up to 7 in a standard dice, but here the dice has numbers 5, 3, 6, 7, 9, and 2, which are not standard. To find the number opposite to 5, we analyze the two given positions of the dice (not shown here but assumed given in the question). By observing the adjacent faces visible with 5, we can eliminate those numbers as opposites. The face opposite to 5 cannot be adjacent to it. From the given numbers, 5 is adjacent to 3, 6, and 7 (from the two positions). The remaining numbers are 9 and 2. Since 9 is adjacent to 7 in one position, it cannot be opposite to 5. Therefore, the number opposite to 5 is 2.

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