A tank is filled in 45 minutes by two pipes, A and B. Pipe B fills the tank twice as fast as A. How much time (in minutes) will pipe A alone take to fill the tank?

Question

Accepted Answer

Let the time taken by pipe A alone to fill the tank be x minutes.

Then, pipe A's rate = 1/x (tank per minute).
Pipe B fills twice as fast as A, so pipe B's rate = 2/x.

Combined rate of A and B = 1/x + 2/x = 3/x.

Given, together they fill the tank in 45 minutes, so combined rate = 1/45.

Therefore, 3/x = 1/45
=> x = 3 * 45 = 135 minutes.

Hence, pipe A alone will take 135 minutes to fill the tank.

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