In triangle XYZ, A is a point on YZ such that XA = YA. If ∠XYA = 50° and ∠AXZ = 19°, what is the degree measure of ∠XZA?

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**Solution:**
**Step 1:** Since XA = YA, triangle XYA is isosceles. The angles opposite the equal sides are equal.
So ∠YXA = ∠XYA = 50°
**Step 2:** In triangle XYA, sum of angles = 180°
∠YXA + ∠XYA + ∠XAY = 180°
50° + 50° + ∠XAY = 180°
∠XAY = 80°
**Step 3:** Since Y, A, Z are collinear, ∠XAY and ∠XAZ form a linear pair.
∠XAZ = 180° - 80° = 100°
**Step 4:** In triangle XAZ, sum of angles = 180°
∠XAZ + ∠AXZ + ∠XZA = 180°
100° + 19° + ∠XZA = 180°
∠XZA = 180° - 119° = 61°
**The correct answer is 61°**

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