In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is

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Let the ratio of manufacturing employees to non-manufacturing employees be $$1:4$$, as 20% of employees work in manufacturing. Assume their numbers are $$x$$ and $$4x$$, respectively.

The total salary obtained by manufacturing employees is one-sixth of the total salary, so the ratio of total salaries of manufacturing to non-manufacturing employees is $$1:5$$. Let their salaries be $$y$$ and $$5y$$, respectively.

The average salary for manufacturing employees is $$\frac{y}{x}$$, and for non-manufacturing employees, it is $$\frac{5y}{4x}$$. The ratio of their average salaries is:  
$$
\frac{y/x}{5y/4x} = \frac{1}{5/4} = \frac{4}{5}
$$

Thus, the ratio of average salaries is **4:5**.

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