Ravi is driving at a speed of 40 km/h on a road. Vijay is 54 meters behind Ravi and driving in the same direction as Ravi. Ashok is driving along the same road from the opposite direction at a speed of 50 km/h and is 225 meters away from Ravi. The speed, in km/h, at which Vijay should drive so that all three cross each other at the same time, is

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The given data includes:  
- Speed of Ravi = $$40 \, 	ext{km/h} = \frac{100}{9} \, 	ext{m/s}$$  
- Speed of Ashok = $$50 \, 	ext{km/h} = \frac{125}{9} \, 	ext{m/s}$$  
- Distance between Ravi and Ashok = $$225 \, 	ext{m}$$  
- Vijay is $$54 \, 	ext{m}$$ behind Ravi.

### Step 1: Calculate the relative speed of Ravi and Ashok.  
Since they are moving in opposite directions:  
$$
	ext{Relative speed} = \frac{100}{9} + \frac{125}{9} = \frac{225}{9} = 25 \, 	ext{m/s}.
$$

### Step 2: Time for Ravi and Ashok to meet.  
$$
	ext{Time} = \frac{	ext{Distance}}{	ext{Relative Speed}} = \frac{225}{25} = 9 \, 	ext{seconds}.
$$

### Step 3: Distance traveled by Ravi in these 9 seconds.  
$$
	ext{Distance by Ravi} = \frac{100}{9} 	imes 9 = 100 \, 	ext{m}.
$$

### Step 4: Total distance Vijay needs to cover in the same time.  
Vijay must cover the distance traveled by Ravi (100 m) plus his initial lag (54 m):  
$$
	ext{Total distance for Vijay} = 100 + 54 = 154 \, 	ext{m}.
$$

### Step 5: Speed of Vijay.  
Vijay's speed can be calculated as:  
$$
	ext{Speed of Vijay} = \frac{	ext{Distance}}{	ext{Time}} = \frac{154}{9} \, 	ext{m/s}.
$$

Convert this to km/h:  
$$
	ext{Speed in km/h} = \frac{154}{9} 	imes \frac{18}{5} = \frac{308}{5} = 61.6 \, 	ext{km/h}.
$$

Thus, the required speed of Vijay is **61.6 km/h**, which corresponds to option **D**.

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