The population of a place increased to 50,000 from 2016 to 2018 at a rate of 6\% per annum, and this growth rate continued for the next 3 years. If *A* is the population in 2016 and *B* is the population in 2020, both rounded to the nearest integer, what is the value of *B - A*?

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**Solution:**

1. Let the population in 2016 be *A*.

2. Given the population in 2018 is 50,000 and the annual growth rate is 6\%.

3. Using the compound growth formula:
   $$	ext{Population in 2018} = A 	imes \left(1 + \frac{6}{100}ight)^2 = A 	imes 1.1236$$

4. Since population in 2018 is 50,000:
   $$1.1236A = 50000 \implies A = \frac{50000}{1.1236} \approx 44500$$

5. To find the population in 2020 (*B*), which is 2 years after 2018, apply the growth again:
   $$B = 50000 	imes \left(1 + \frac{6}{100}ight)^2 = 50000 	imes 1.1236 = 56180$$

6. Calculate the difference:
   $$B - A = 56180 - 44500 = 11680$$

**Answer:** 11680

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