What is the average of the first 91 even numbers?

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**Solution:**

1. The first 91 even numbers are: 2, 4, 6, ..., up to the 91st even number.

2. The nth even number is given by the formula: $2n$. So, the 91st even number is $2 	imes 91 = 182$.

3. The average of the first n even numbers can be found by calculating the mean of the first and last even numbers:
   $$	ext{Average} = \frac{2 + 182}{2} = \frac{184}{2} = 92$$

4. Alternatively, the average of the first n even numbers is equal to $n + 1$, which for $n=91$ is $91 + 1 = 92$.

**Answer:** 92

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