Anil mixes cocoa with sugar in the ratio 3:2 to prepare mixture A, and coffee with sugar in the ratio 7:3 to prepare mixture B. He combines mixtures A and B in the ratio 2:3 to make a new mixture C. If he mixes C with an equal amount of milk to make a drink, then the percentage of sugar in this drink will be:

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1. **Mixing Mixtures A and B**:
   - Mixture A has cocoa and sugar in the ratio 3:2. For every 20 kg of mixture A, it contains:
     - Cocoa = $$ \frac{3}{5} 	imes 20 = 12 $$ kg
     - Sugar = $$ \frac{2}{5} 	imes 20 = 8 $$ kg
   - Mixture B has coffee and sugar in the ratio 7:3. For every 30 kg of mixture B, it contains:
     - Coffee = $$ \frac{7}{10} 	imes 30 = 21 $$ kg
     - Sugar = $$ \frac{3}{10} 	imes 30 = 9 $$ kg

Total sugar in mixture C (combined in a ratio of 2:3):
   - Sugar from A = $$ 8 $$ kg
   - Sugar from B = $$ 9 $$ kg
   - Total sugar = $$ 8 + 9 = 17 $$ kg

2. **Mixing Mixture C with Milk**:
   - Mixture C (50 kg) is mixed with an equal amount of milk (50 kg). Milk contains no sugar.
   - Total weight of the new drink = $$ 50 + 50 = 100 $$ kg.
   - Percentage of sugar in the drink:
     $$
     	ext{Percentage of sugar} = \frac{17}{100} 	imes 100 = 17\%
     $$

Thus, the percentage of sugar in the drink is **17%**, corresponding to option **D**.

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