Which number among 38211, 38121, 32118, and 31128 is divisible by 24?

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Accepted Answer

**Solution:**

1. A number is divisible by 24 if it is divisible by both 3 and 8.

2. **Divisibility by 3:** The sum of the digits of the number must be divisible by 3.

3. **Divisibility by 8:** The last three digits of the number must be divisible by 8.

4. Check each number:

- For 38211:
     - Sum of digits = 3 + 8 + 2 + 1 + 1 = 15 (divisible by 3)
     - Last three digits = 211 (not divisible by 8)
     - So, 38211 is not divisible by 24.

- For 38121:
     - Sum of digits = 3 + 8 + 1 + 2 + 1 = 15 (divisible by 3)
     - Last three digits = 121 (not divisible by 8)
     - So, 38121 is not divisible by 24.

- For 32118:
     - Sum of digits = 3 + 2 + 1 + 1 + 8 = 15 (divisible by 3)
     - Last three digits = 118 (not divisible by 8)
     - So, 32118 is not divisible by 24.

- For 31128:
     - Sum of digits = 3 + 1 + 1 + 2 + 8 = 15 (divisible by 3)
     - Last three digits = 128 (divisible by 8)
     - Hence, 31128 is divisible by 24.

**Answer:** 31128

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