A man sells a mobile phone for ₹680 and incurs a loss. If he had sold it for ₹1070, his profit would have been twice the amount of the earlier loss. What is the **cost price** of the mobile phone (in ₹)?

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**Solution:**

1. Let the cost price of the mobile phone be ₹*C*.

2. Since the phone is sold at ₹680 with a loss, the loss amount is:
   
   $$	ext{Loss} = C - 680$$

3. If the phone were sold at ₹1070, there would be a gain, which is:

$$	ext{Gain} = 1070 - C$$

4. According to the problem, this gain is twice the earlier loss:

$$1070 - C = 2 	imes (C - 680)$$

5. Simplify the equation:

$$1070 - C = 2C - 1360$$

$$1070 + 1360 = 2C + C$$

$$2430 = 3C$$

6. Solve for *C*:

$$C = \frac{2430}{3} = 810$$

**Answer:** ₹810

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