Two years ago, the population of a town was $9,487,500$. Due to migration to big cities, the population decreases every year at the rate of $8\%$. What is the present population of the town?

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**Solution:**

1. Given the initial population two years ago, $P_0 = 9,487,500$, and the annual decrease rate, $R = 8\%$.

2. The population decreases each year by $8\%$, so the population after $t$ years is given by the formula:

$$P_t = P_0 	imes \left(1 - \frac{R}{100}ight)^t$$

3. Substitute the values:

$$P_2 = 9,487,500 	imes \left(1 - \frac{8}{100}ight)^2 = 9,487,500 	imes (0.92)^2$$

4. Calculate $(0.92)^2 = 0.8464$.

5. Multiply:

$$P_2 = 9,487,500 	imes 0.8464 = 8,030,220$$

**Answer:** The current population of the town is $8,030,220$.

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