Which number among **38211**, **38121**, **32118**, and **31128** is divisible by 24?

Question

Accepted Answer

**Solution:**

1. A number is divisible by 24 if it is divisible by both 3 and 8.

2. **Divisibility by 3:** Sum of digits should be divisible by 3.

3. **Divisibility by 8:** Last three digits of the number should be divisible by 8.

4. Check each number:

- **38211:** Sum of digits = 3 + 8 + 2 + 1 + 1 = 15 (divisible by 3)
     - Last three digits = 211, which is not divisible by 8
     - So, 38211 is not divisible by 24.

- **38121:** Sum of digits = 3 + 8 + 1 + 2 + 1 = 15 (divisible by 3)
     - Last three digits = 121, which is not divisible by 8
     - So, 38121 is not divisible by 24.

- **32118:** Sum of digits = 3 + 2 + 1 + 1 + 8 = 15 (divisible by 3)
     - Last three digits = 118, which is not divisible by 8
     - So, 32118 is not divisible by 24.

- **31128:** Sum of digits = 3 + 1 + 1 + 2 + 8 = 15 (divisible by 3)
     - Last three digits = 128, which is divisible by 8
     - So, 31128 is divisible by 24.

**Answer:** 31128

Answer

Answer

Answer