Two years ago, the population of a town was 9,487,500. Due to migration to big cities, it decreases every year at the rate of 8%. What is the present population of the town?

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**Solution:**

1. Given:
   - Population two years ago, $ P = 9,487,500 $
   - Annual decrease rate, $ r = 8\% = 0.08 $
   - Time, $ t = 2 $ years

2. The population decreases every year by 8%, so the present population is calculated using the formula for exponential decay:

$$\text{Present Population} = P \times (1 - r)^t$$

3. Substitute the values:

$$= 9,487,500 \times (1 - 0.08)^2 = 9,487,500 \times (0.92)^2$$

4. Calculate $ (0.92)^2 $:

$$0.92 \times 0.92 = 0.8464$$

5. Calculate the present population:

$$9,487,500 \times 0.8464 = 8,030,220$$

**Answer:** The present population is $8,030,220$.

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