At a certain time in a park, the number of heads and the number of legs of monkeys and human visitors were counted, and it was found that there were 54 heads and 148 legs. Find the number of monkeys in the park.

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**Solution:**

1. Let the number of monkeys be *x* and the number of humans be *y*.

2. Each monkey has 1 head and 4 legs, each human has 1 head and 2 legs.

3. From the problem, we have two equations:
   - Total heads: $$x + y = 54$$
   - Total legs: $$4x + 2y = 148$$

4. Multiply the first equation by 2:
   $$2x + 2y = 108$$

5. Subtract this from the second equation:
   $$4x + 2y - (2x + 2y) = 148 - 108$$
   $$2x = 40$$
   $$x = 20$$

6. Substitute *x = 20* into the first equation:
   $$20 + y = 54$$
   $$y = 34$$

7. Therefore, the number of monkeys in the park is **20**.

**Answer:** 20

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