Hari, Kamal, and Lalit contested an election in which 6050 votes were polled and none of the votes were invalid. Kamal got 42\% more votes than the total votes obtained by Hari and Lalit together. If Lalit obtained only 8\% of the total polled votes, find the number of votes obtained by Hari.

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**Solution:**

1. Calculate Lalit's votes:
   - Total votes = 6050
   - Lalit's votes = 8\% of 6050 = $6050 	imes 0.08 = 484$

2. Let Hari's votes be $H$, Kamal's votes be $K$.

3. Total votes sum up to:
   $$H + K + L = 6050$$
   Substitute $L = 484$:
   $$H + K + 484 = 6050 \implies H + K = 6050 - 484 = 5566$$

4. Kamal got 42\% more votes than the sum of Hari's and Lalit's votes:
   $$K = 1.42(H + L) = 1.42(H + 484)$$

5. Substitute $K$ in the equation $H + K = 5566$:
   $$H + 1.42(H + 484) = 5566$$
   $$H + 1.42H + 1.42 	imes 484 = 5566$$
   $$2.42H + 687.28 = 5566$$

6. Solve for $H$:
   $$2.42H = 5566 - 687.28 = 4878.72$$
   $$H = \frac{4878.72}{2.42} = 2016$$

**Answer:** Hari obtained **2016** votes.

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