A vessel contains 139.96 litres of a mixture of milk and water, where 80\% of the mixture is milk. If 24.96\% of the mixture is taken out and then 19 litres of water is added, what is the approximate percentage of water in the new mixture?

Question

Accepted Answer

**Solution:**

1. The total volume of the mixture is approximately taken as 140 litres for ease of calculation.

2. Calculate the quantities of milk and water initially:
   - Milk = 80\% of 140 = 112 litres
   - Water = 20\% of 140 = 28 litres

3. When 24.96\% (approximately 25\%) of the mixture is removed, the quantities removed are proportional:
   - Amount removed = 25\% of 140 = 35 litres
   - Milk removed = 25\% of 112 = 28 litres
   - Water removed = 25\% of 28 = 7 litres

4. Remaining quantities after removal:
   - Milk = 112 - 28 = 84 litres
   - Water = 28 - 7 = 21 litres

5. Now, 19 litres of water is added to the remaining mixture:
   - New water quantity = 21 + 19 = 40 litres
   - Milk remains 84 litres

6. Total volume of the new mixture = 84 + 40 = 124 litres

7. Calculate the percentage of water in the new mixture:
   $$	ext{Water \%} = \left( \frac{40}{124} ight) 	imes 100 \approx 32\%$$

**Answer:** 32\%

Answer

Answer

Answer