The total number of students in three schools A, B, and C is 350, with 150 students in school B. Boys in A are equal to girls in C. Boys in C are equal to girls in A, which is 25. School B has an equal number of boys and girls. In school A, 20\% of boys did not appear for the exam, which is 5 more than the number of girls who appeared. In school B, the number of girls who did not appear is equal to the number of boys who did not appear. The total number of students who did not appear in the exam is 40. In school C, the ratio of students who did not appear to those who appeared is 1:1, and 45 girls did not appear for the exam.
What percentage of the total girls in school C is the total number of boys in schools A and B together?

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**Solution:**

1. From the problem, the total students are 350 with 150 in school B.

2. Given:
   - Boys in A = Girls in C
   - Boys in C = Girls in A = 25
   - Boys and girls in B are equal, so boys in B = girls in B = 75 (since total in B is 150)

3. Total students in A and C are 100 each (350 - 150 = 200, split as 100 each).

4. Since girls in A = 25, boys in C = 25.

5. Boys in A = girls in C. Total girls in C = 75, so boys in A = 75.

6. Total boys in A and B = boys in A + boys in B = 75 + 75 = 150.

7. Total girls in C = 75.

8. Calculate the required percentage:
   $$\frac{	ext{Total boys in A and B}}{	ext{Total girls in C}} 	imes 100 = \frac{150}{75} 	imes 100 = 200\%$$

**Answer:** 200\%![image.png](https://res.cloudinary.com/aptidude/image/upload/v1755859076/aptidude_questions/cswdtughnn7bmuxw7gej.png)

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