Karan invested Rs 9000 in scheme A at an interest rate of $(x+2)\%$ per annum and Rs 12000 in scheme B at an interest rate of $(x-2)\%$ per annum. Both schemes offer simple interest. After 5 years, the interest earned from both schemes is the same. Find the value of $x$.

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**Solution:**

1. Let the rate of interest for scheme A be $(x+2)\%$ per annum and for scheme B be $(x-2)\%$ per annum.

2. The simple interest formula is:
   $$	ext{Simple Interest} = \frac{	ext{Principal} 	imes 	ext{Rate} 	imes 	ext{Time}}{100}$$

3. Interest from scheme A after 5 years:
   $$SI_A = \frac{9000 	imes (x+2) 	imes 5}{100} = 450 	imes (x+2)$$

4. Interest from scheme B after 5 years:
   $$SI_B = \frac{12000 	imes (x-2) 	imes 5}{100} = 600 	imes (x-2)$$

5. Since the interests are equal:
   $$450(x+2) = 600(x-2)$$

6. Expanding both sides:
   $$450x + 900 = 600x - 1200$$

7. Rearranging terms:
   $$900 + 1200 = 600x - 450x$$
   $$2100 = 150x$$

8. Solving for $x$:
   $$x = \frac{2100}{150} = 14$$

**Answer:** $14$

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