A, B, and C together can complete a work in 4 days, while B alone can finish the same work in 24 days. If the efficiency of C is 300\% more than that of B, what is the difference between the number of days taken by A and C to complete the work individually?

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**Solution:**

1. Assume the total work as the LCM of 4 and 24, which is 24 units.

2. The combined efficiency of A, B, and C is:
   $$\frac{24 	ext{ units}}{4 	ext{ days}} = 6 	ext{ units/day}$$

3. Efficiency of B alone is:
   $$\frac{24 	ext{ units}}{24 	ext{ days}} = 1 	ext{ unit/day}$$

4. Since C's efficiency is 300\% more than B's, C's efficiency is:
   $$1 + 3 	imes 1 = 4 	ext{ units/day}$$

5. Efficiency of A is the remaining part:
   $$6 - 1 - 4 = 1 	ext{ unit/day}$$

6. Time taken by A to complete the work alone:
   $$\frac{24}{1} = 24 	ext{ days}$$

7. Time taken by C to complete the work alone:
   $$\frac{24}{4} = 6 	ext{ days}$$

8. The difference in days taken by A and C is:
   $$24 - 6 = 18 	ext{ days}$$

**Answer:** 18

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