The combined cost price of two articles A and B is Rs. 350. Both articles are marked up by 60% over their cost prices. If the marked price of article B exceeds that of article A by Rs. 80, what is the cost price of article A?

Question

Accepted Answer

**Solution:**

1. Let the cost price of article A be $5x$ and that of article B be $5y$.

2. Since both articles are marked up by 60%, their marked prices are:
   - Article A: $5x 	imes \frac{160}{100} = 8x$
   - Article B: $5y 	imes \frac{160}{100} = 8y$

3. Given that the sum of cost prices is Rs. 350:
   $$5x + 5y = 350 \implies x + y = 70 \quad (1)$$

4. The difference in marked prices is Rs. 80:
   $$8y - 8x = 80 \implies y - x = 10 \quad (2)$$

5. Solve equations (1) and (2):
   - From (2): $y = x + 10$
   - Substitute into (1): $x + (x + 10) = 70 \implies 2x + 10 = 70 \implies 2x = 60 \implies x = 30$
   - Then $y = 30 + 10 = 40$

6. Therefore, cost price of article A:
   $$5x = 5 	imes 30 = 150 	ext{ Rs.}$$

**Note:** The original problem solution had $y - x = 8$, but based on the given data, the difference in marked prices is Rs. 80, so $8y - 8x = 80 \Rightarrow y - x = 10$. Using this corrected value, the cost price of article A is Rs. 150.

**Answer:** Rs. 150

Answer

Answer

Answer

Answer