Read the following pie chart and bar graph carefully and answer the questions given below. The bar graph shows total number of magazines and newspapers published by five different publishers. The pie chart shows the percentage distribution of the newspapers published by these publishers. Note: The total number of magazines published by A is 50.

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1755080917/aptidude_questions/dvz2maxbeupbc1sl8t5d.png)
![image.png](https://res.cloudinary.com/aptidude/image/upload/v1755080932/aptidude_questions/fg3jv2vstpvqj9djcyla.png)

The total number of magazines published by B and F together 12X. Find the average number of magazines published by F and D.

Question

Read the following pie chart and bar graph carefully and answer the questions given below. The bar graph shows total number of magazines and newspapers published by five different publishers. The pie chart shows the percentage distribution of the newspapers published by these publishers. Note: The total number of magazines published by A is 50.

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1755080917/aptidude_questions/dvz2maxbeupbc1sl8t5d.png)
![image.png](https://res.cloudinary.com/aptidude/image/upload/v1755080932/aptidude_questions/fg3jv2vstpvqj9djcyla.png)

The total number of magazines published by B and F together 12X. Find the average number of magazines published by F and D.

Accepted Answer

**Solution:**

1. Given that $X = 15$, the total magazines published by F is:
   $$12X = 12 	imes 15 = 180$$

2. The total magazines published by D is given as 180.

3. To find the average number of magazines published by F and D:
   $$	ext{Average} = \frac{	ext{Magazines by F} + 	ext{Magazines by D}}{2} = \frac{180 + 180}{2} = \frac{360}{2} = 180$$

4. However, the question states the average number of magazines published by F and D, but the options suggest a different interpretation. Since the problem states "The total number of magazines published by B and F together 12X," and from the data, magazines published by B is 140, so magazines published by F:
   $$	ext{Magazines by F} = 12X - 	ext{Magazines by B} = 180 - 140 = 40$$

5. Now, average magazines published by F and D:
   $$\frac{40 + 180}{2} = \frac{220}{2} = 110$$

**Answer:** 110

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