In the number $85274369$, each odd digit is decreased by $1$ and each even digit is decreased by $2$. After these changes, the digits are rearranged to form a new number. What is the sum of the digits that appear only once in this new number?

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**Solution:**

1. Original number: $85274369$

2. Identify odd and even digits:
   - Odd digits: $5, 7, 3, 9$
   - Even digits: $8, 2, 4, 6$

3. Decrease each odd digit by $1$:
   - $5 - 1 = 4$
   - $7 - 1 = 6$
   - $3 - 1 = 2$
   - $9 - 1 = 8$

4. Decrease each even digit by $2$:
   - $8 - 2 = 6$
   - $2 - 2 = 0$
   - $4 - 2 = 2$
   - $6 - 2 = 4$

5. Replace digits in the original number with the new values:
   - $8 	o 6$
   - $5 	o 4$
   - $2 	o 0$
   - $7 	o 6$
   - $4 	o 2$
   - $3 	o 2$
   - $6 	o 4$
   - $9 	o 8$

6. New digits are: $6, 4, 0, 6, 2, 2, 4, 8$

7. Rearrange the digits (order does not affect sum of unique digits):
   - Digits and their frequencies:
     - $0$: 1 time
     - $2$: 2 times
     - $4$: 2 times
     - $6$: 2 times
     - $8$: 1 time

8. Digits that are not repeated (appear only once) are $0$ and $8$.

9. Sum of these digits:
   $$0 + 8 = 8$$

**Answer:** $8$

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