X liters of milk is taken out and replaced with water from a container having 240 liters of milk. Then, 20\% of the mixture is taken out and replaced with water. In the final mixture, the difference in quantity of milk and water is 128 liters. Find the value of X.

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**Solution:**

1. Initially, the container has 240 liters of milk.

2. When *X* liters of milk is taken out and replaced with water:
   - Milk left = $240 - X$ liters
   - Water = $X$ liters

3. Then, 20\% of the mixture is taken out and replaced with water. After removing 20\%:
   - Remaining milk = $\frac{80}{100} \times (240 - X) = 192 - 0.8X$ liters
   - Remaining water = $\frac{80}{100} \times X + \frac{20}{100} \times 240 = 0.8X + 48$ liters

4. According to the question, the difference between milk and water in the final mixture is 128 liters:

$$
   (192 - 0.8X) - (0.8X + 48) = 128
   $$

5. Simplify the equation:

$$
   192 - 0.8X - 0.8X - 48 = 128
   $$

$$
   144 - 1.6X = 128
   $$

$$
   144 - 128 = 1.6X
   $$

$$
   16 = 1.6X
   $$

$$
   X = \frac{16}{1.6} = 10
   $$

**Answer:** 10

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