Train ‘A’ running at speed of 54 km/hr crosses a platform of length same as that of the train in 36
sec. If train B, which is 230 meters long crosses the same platform in 25 sec, then find speed of train B (in km/hr)?

Question

Accepted Answer

**Solution:**

1. Let the length of train A and the platform each be *L* meters.

2. Train A crosses the platform in 36 seconds at 54 km/hr. Convert speed to m/s:
   $$54 	imes \frac{5}{18} = 15 	ext{ m/s}$$

3. Total distance covered by train A while crossing the platform is the sum of the lengths of the train and platform:
   $$L + L = 2L$$

4. Using the formula speed = distance/time:
   $$\frac{2L}{36} = 15 \implies 2L = 15 	imes 36 = 540 \implies L = 270 	ext{ meters}$$

5. For train B, length = 230 meters, time to cross platform = 25 seconds, and platform length = 270 meters.

6. Total distance covered by train B while crossing the platform:
   $$230 + 270 = 500 	ext{ meters}$$

7. Let speed of train B be *s* km/hr. Convert speed to m/s:
   $$s 	imes \frac{5}{18}$$

8. Using speed = distance/time:
   $$\frac{500}{25} = s 	imes \frac{5}{18} \implies 20 = s 	imes \frac{5}{18}$$

9. Solve for *s*:
   $$s = \frac{20 	imes 18}{5} = 72 	ext{ km/hr}$$

**Answer:** $72 	ext{ km/hr}$

Answer

Answer

Answer

Answer