Given the table below showing the number of items A sold and the percentage of items B and C sold by a store on different days of the week, find the percentage by which the total items C sold on Wednesday exceed the total items C sold on Monday and Tuesday combined.

| Days | Items A | % of items B | % of items C |
|-----------|---------|--------------|--------------|
| Monday | 240 | 32\% | 20\% |
| Tuesday | 320 | 48\% | 12\% |
| Wednesday | 420 | 45\% | 20\% |
| Thursday | 360 | 56\% | 20\% |
| Friday | 340 | 22\% | 10\% |

What is the percentage increase of items C sold on Wednesday compared to the total items C sold on Monday and Tuesday together?

Question

Given the table below showing the number of items A sold and the percentage of items B and C sold by a store on different days of the week, find the percentage by which the total items C sold on Wednesday exceed the total items C sold on Monday and Tuesday combined.

| Days      | Items A | % of items B | % of items C |
|-----------|---------|--------------|--------------|
| Monday    | 240     | 32\%        | 20\%        |
| Tuesday   | 320     | 48\%        | 12\%        |
| Wednesday | 420     | 45\%        | 20\%        |
| Thursday  | 360     | 56\%        | 20\%        |
| Friday    | 340     | 22\%        | 10\%        |

What is the percentage increase of items C sold on Wednesday compared to the total items C sold on Monday and Tuesday together?

Accepted Answer

**Solution:**

1. Calculate total items C sold on Wednesday:
   - Total items sold on Wednesday = Items A + Items B + Items C
   - Since percentages of B and C are given relative to total items sold, let total items sold on Wednesday be *T*.
   - Items A on Wednesday = 420
   - Percentage of items B = 45\%, items C = 20\%
   - Therefore, total items sold on Wednesday = $ \frac{420}{1 - 0.45 - 0.20} = \frac{420}{0.35} = 1200 $
   - Items C sold on Wednesday = 20\% of 1200 = $ 0.20 \times 1200 = 240 $

2. Calculate total items C sold on Monday and Tuesday together:

- For Monday:
     - Items A = 240
     - % of items B = 32\%, items C = 20\%
     - Total items sold on Monday = $ \frac{240}{1 - 0.32 - 0.20} = \frac{240}{0.48} = 500 $
     - Items C on Monday = 20\% of 500 = 100

- For Tuesday:
     - Items A = 320
     - % of items B = 48\%, items C = 12\%
     - Total items sold on Tuesday = $ \frac{320}{1 - 0.48 - 0.12} = \frac{320}{0.40} = 800 $
     - Items C on Tuesday = 12\% of 800 = 96

- Total items C on Monday and Tuesday = 100 + 96 = 196

3. Calculate the percentage increase:

$$
   \text{Percentage increase} = \frac{240 - 196}{196} \times 100 = \frac{44}{196} \times 100 \approx 22.45\% 
   $$

**Answer:** 22\%

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