Ratio of present ages of A and B is $16:7$. After $12$ years, A's age is twice of B's age. Find the present ages of A and B.

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**Solution:**

1. Let the present ages of A and B be $16x$ years and $7x$ years respectively, as given by the ratio $16:7$.

2. After 12 years, their ages will be:
   - A's age: $16x + 12$
   - B's age: $7x + 12$

3. According to the problem, after 12 years, A's age is twice B's age:
   $$16x + 12 = 2(7x + 12)$$

4. Simplify the equation:
   $$16x + 12 = 14x + 24$$

5. Rearranging terms:
   $$16x - 14x = 24 - 12$$
   $$2x = 12$$
   $$x = 6$$

6. Calculate present ages:
   - A's present age: $16 	imes 6 = 96$ years
   - B's present age: $7 	imes 6 = 42$ years

**Answer:** $96 	ext{ yr}; 42 	ext{ yr}$

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