A mixture of milk and water in a jar contains 28 L milk and 8 L water. $X$ L milk and $X$ L water are mixed to form a new mixture. If 40\% of the new mixture is 20 L, then find the value of $X$.

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**Solution:**

1. Let the amount of milk and water added be $X$ liters each.

2. Initial mixture contains:
   - Milk = 28 L
   - Water = 8 L

3. After adding $X$ L milk and $X$ L water, the total mixture becomes:
   $$28 + X + 8 + X = 36 + 2X 	ext{ liters}$$

4. Given that 40\% of the new mixture is 20 L:
   $$40\% 	imes 	ext{new mixture} = 20$$

5. Calculate the total new mixture volume:
   $$	ext{new mixture} = \frac{20}{40\%} = \frac{20}{0.4} = 50 	ext{ L}$$

6. Set up the equation:
   $$36 + 2X = 50$$

7. Solve for $X$:
   $$2X = 50 - 36 = 14$$
   $$X = \frac{14}{2} = 7 	ext{ L}$$

**Answer:** $7$ L

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